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4x^2+x+75=180
We move all terms to the left:
4x^2+x+75-(180)=0
We add all the numbers together, and all the variables
4x^2+x-105=0
a = 4; b = 1; c = -105;
Δ = b2-4ac
Δ = 12-4·4·(-105)
Δ = 1681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1681}=41$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-41}{2*4}=\frac{-42}{8} =-5+1/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+41}{2*4}=\frac{40}{8} =5 $
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